Mendenhall AFC Player Of The Week
PITTSBURGH (93-7 The FAN) — Steelers running back Rashard Mendenhall was chosen as AFC Player of the Week after his 146-yard performance against Jacksonville Sunday.
In a 17-13 win against the Jaguars, Mendenhall toted the ball 23 times for a 6.3-yard per carry average and one touchdown. It was the fourth-highest single-game rushing performance of his career.
Highlighting his performance was a 68-yard run through the Jacksonville defense and down left sideline that set up a 21-yard field to give the Steelers a 17-0 lead in the second quarter. Mendenhall went over 100 yards in the first half for the first time in his career.
It's the second time in Mendenhall's career that he has received Player of the Week honors. It's also the second week in a row a Steeler has earned Offensive Player of the Week, as quarterback Ben Roethlisberger received the honor for his five-touchdown performance against Tennessee in Week 5.
